AC Voltage and Current Diagram
About points...
We associate a certain number of points with each exercise.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
About difficulty...
We associate a certain difficulty with each exercise.
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
Question
Solution
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Exercise:
Using the diagram answer the following questions: center includegraphicswidth.cm#image_path:ac-voltagcurrent# center abcliste abc Read the amplitude and the period of the voltage signal red line and of the current signal blue line from the diagram. Calculate the circuit's impedance. abc Read the time shift from the diagram and calculate the phase shift between current and voltage. What could the circuit look like? abc Calculate the apparent power and the effective power. abcliste
Solution:
abcliste abc The voltage and current amplitudes are V_ resultVO I_ resultIO The period is T resultTO The impedance can be calculated as Z ZF fracVI Z approx resultZP abc The time shift between current and voltage is Delta t resultdtO The phase shift fulfills the condition fracDeltaphipi fracDelta tT Solving for the phase shift leads to Deltaphi dphiF pifracdtT dphi approx resultdphiPresultdphidegP The current lags behind the voltage so the circuit could consist of a resistor and a coil in series. abc The apparent power is given by S sscVrmssscIrms SF fracVtimesI S approx resultSP P sscVrmssscIrmscosDeltaphi PF fracVtimesItimescosdphi P approx resultPP abcliste
Using the diagram answer the following questions: center includegraphicswidth.cm#image_path:ac-voltagcurrent# center abcliste abc Read the amplitude and the period of the voltage signal red line and of the current signal blue line from the diagram. Calculate the circuit's impedance. abc Read the time shift from the diagram and calculate the phase shift between current and voltage. What could the circuit look like? abc Calculate the apparent power and the effective power. abcliste
Solution:
abcliste abc The voltage and current amplitudes are V_ resultVO I_ resultIO The period is T resultTO The impedance can be calculated as Z ZF fracVI Z approx resultZP abc The time shift between current and voltage is Delta t resultdtO The phase shift fulfills the condition fracDeltaphipi fracDelta tT Solving for the phase shift leads to Deltaphi dphiF pifracdtT dphi approx resultdphiPresultdphidegP The current lags behind the voltage so the circuit could consist of a resistor and a coil in series. abc The apparent power is given by S sscVrmssscIrms SF fracVtimesI S approx resultSP P sscVrmssscIrmscosDeltaphi PF fracVtimesItimescosdphi P approx resultPP abcliste
Meta Information
Exercise:
Using the diagram answer the following questions: center includegraphicswidth.cm#image_path:ac-voltagcurrent# center abcliste abc Read the amplitude and the period of the voltage signal red line and of the current signal blue line from the diagram. Calculate the circuit's impedance. abc Read the time shift from the diagram and calculate the phase shift between current and voltage. What could the circuit look like? abc Calculate the apparent power and the effective power. abcliste
Solution:
abcliste abc The voltage and current amplitudes are V_ resultVO I_ resultIO The period is T resultTO The impedance can be calculated as Z ZF fracVI Z approx resultZP abc The time shift between current and voltage is Delta t resultdtO The phase shift fulfills the condition fracDeltaphipi fracDelta tT Solving for the phase shift leads to Deltaphi dphiF pifracdtT dphi approx resultdphiPresultdphidegP The current lags behind the voltage so the circuit could consist of a resistor and a coil in series. abc The apparent power is given by S sscVrmssscIrms SF fracVtimesI S approx resultSP P sscVrmssscIrmscosDeltaphi PF fracVtimesItimescosdphi P approx resultPP abcliste
Using the diagram answer the following questions: center includegraphicswidth.cm#image_path:ac-voltagcurrent# center abcliste abc Read the amplitude and the period of the voltage signal red line and of the current signal blue line from the diagram. Calculate the circuit's impedance. abc Read the time shift from the diagram and calculate the phase shift between current and voltage. What could the circuit look like? abc Calculate the apparent power and the effective power. abcliste
Solution:
abcliste abc The voltage and current amplitudes are V_ resultVO I_ resultIO The period is T resultTO The impedance can be calculated as Z ZF fracVI Z approx resultZP abc The time shift between current and voltage is Delta t resultdtO The phase shift fulfills the condition fracDeltaphipi fracDelta tT Solving for the phase shift leads to Deltaphi dphiF pifracdtT dphi approx resultdphiPresultdphidegP The current lags behind the voltage so the circuit could consist of a resistor and a coil in series. abc The apparent power is given by S sscVrmssscIrms SF fracVtimesI S approx resultSP P sscVrmssscIrmscosDeltaphi PF fracVtimesItimescosdphi P approx resultPP abcliste
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