Force and Torque on Dipole
About points...
We associate a certain number of points with each exercise.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
About difficulty...
We associate a certain difficulty with each exercise.
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
Question
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Exercise:
Find the net force and torque acting on an electric dipole in a uniform electric field. center includegraphicswidthtextwidth#image_path:dipolforctorqu# center
Solution:
The forces acting on the positive and negative charge of the dipole are equal in magnitude but opposite in direction see figure. center includegraphicswidthtextwidth#image_path:dipolforctorquwith-forces-# center The net force is therefore sscFnet F_+ - F_- The torque caused by the force acting on the positive charge with respect to the midpoin M is tau_+ F_+ fracd sheta The torque caused by the force acting on the negative charge has the same magnitude and acts in the same direction for the example in the figure: clockwise so the net torque is tau tau_+ F_+ d sheta q E d sheta With the electric dipole moment pqd this can be written as tau p E sheta The torque can also be defined as the cross product vectau vecpcrossvecE The direction of this vector is related to the orientation of the torque with the following right-hand rule: When the thumb of the right hand pos in the direction of vectau the fingers define the orientation of the torque.
Find the net force and torque acting on an electric dipole in a uniform electric field. center includegraphicswidthtextwidth#image_path:dipolforctorqu# center
Solution:
The forces acting on the positive and negative charge of the dipole are equal in magnitude but opposite in direction see figure. center includegraphicswidthtextwidth#image_path:dipolforctorquwith-forces-# center The net force is therefore sscFnet F_+ - F_- The torque caused by the force acting on the positive charge with respect to the midpoin M is tau_+ F_+ fracd sheta The torque caused by the force acting on the negative charge has the same magnitude and acts in the same direction for the example in the figure: clockwise so the net torque is tau tau_+ F_+ d sheta q E d sheta With the electric dipole moment pqd this can be written as tau p E sheta The torque can also be defined as the cross product vectau vecpcrossvecE The direction of this vector is related to the orientation of the torque with the following right-hand rule: When the thumb of the right hand pos in the direction of vectau the fingers define the orientation of the torque.
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Exercise:
Find the net force and torque acting on an electric dipole in a uniform electric field. center includegraphicswidthtextwidth#image_path:dipolforctorqu# center
Solution:
The forces acting on the positive and negative charge of the dipole are equal in magnitude but opposite in direction see figure. center includegraphicswidthtextwidth#image_path:dipolforctorquwith-forces-# center The net force is therefore sscFnet F_+ - F_- The torque caused by the force acting on the positive charge with respect to the midpoin M is tau_+ F_+ fracd sheta The torque caused by the force acting on the negative charge has the same magnitude and acts in the same direction for the example in the figure: clockwise so the net torque is tau tau_+ F_+ d sheta q E d sheta With the electric dipole moment pqd this can be written as tau p E sheta The torque can also be defined as the cross product vectau vecpcrossvecE The direction of this vector is related to the orientation of the torque with the following right-hand rule: When the thumb of the right hand pos in the direction of vectau the fingers define the orientation of the torque.
Find the net force and torque acting on an electric dipole in a uniform electric field. center includegraphicswidthtextwidth#image_path:dipolforctorqu# center
Solution:
The forces acting on the positive and negative charge of the dipole are equal in magnitude but opposite in direction see figure. center includegraphicswidthtextwidth#image_path:dipolforctorquwith-forces-# center The net force is therefore sscFnet F_+ - F_- The torque caused by the force acting on the positive charge with respect to the midpoin M is tau_+ F_+ fracd sheta The torque caused by the force acting on the negative charge has the same magnitude and acts in the same direction for the example in the figure: clockwise so the net torque is tau tau_+ F_+ d sheta q E d sheta With the electric dipole moment pqd this can be written as tau p E sheta The torque can also be defined as the cross product vectau vecpcrossvecE The direction of this vector is related to the orientation of the torque with the following right-hand rule: When the thumb of the right hand pos in the direction of vectau the fingers define the orientation of the torque.
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