Messingsorte
About points...
We associate a certain number of points with each exercise.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
About difficulty...
We associate a certain difficulty with each exercise.
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
Question
Solution
Short
Video
\(\LaTeX\)
Need help? Yes, please!
The following quantities appear in the problem:
Masse \(m\) / Volumen \(V\) / Dichte \(\varrho\) / Verhältnis / Anteil \(\eta\) /
The following formulas must be used to solve the exercise:
\(\eta = \dfrac{a}{A} \quad \) \(\varrho = \dfrac{m}{V} \quad \) \(\dfrac{1}{\varrho} = \sum_i \dfrac{w_i}{\varrho_i} \quad \)
No explanation / solution video to this exercise has yet been created.
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Visit our YouTube-Channel to see solutions to other exercises.
Don't forget to subscribe to our channel, like the videos and leave comments!
Exercise:
Eine bestimmte Messingsorte hat eine Dichte von roO. Wie viel Prozent Kupfer und wieviel Prozent Zink enthält sie? Die Dichte von Kupfer ist roCuO diejenige von Zink roSnO.
Solution:
Geg rho roO ro rho_Cu roCuO roCu rho_Sn roSnO roSn GesKupferanteilp_Cusipercent GesZinkanteilp_Snsipercent Für das Gesamtvolumen gilt al V V_rm Cu + V_rm Sn fracmrho fracm_rm Curho_rm Cu + fracm_rm Snrho_rm Sn fracmrho fracp_rm Cu mrho_rm Cu + frac-p_rm Cu mrho_rm Sn Wir können die Masse m wegkürzen und dann nach p_rm Cu auflösen: al fracrho fracp_rm Curho_rm Cu + frac-p_rm Curho_rm Sn uf rho_rm Cu rho_rm Sn fracrho_rm Cu rho_rm Snrho p_rm Cu rho_rm Sn + -p_rm Cu rho_rm Cu uf - rho_rm Cu fracrho_rm Cu rho_rm Snrho - rho_rm Cu p_rm Cu rho_rm Sn - rho_rm Cu uf :rho_rm Sn - rho_rm Cu p_rm Cu fracrho_rm Cu rho_rm Sn - rho rho_rm Curhorho_rm Sn - rho_rm Cu p_Cu pF fracroCu roSn - ro roCuro leftroSn - roCuright p approx pP p_Cu pF pP Aus Symmetriegründen gilt p_Sn qF fracroSn roCu - ro roSnro leftroCu - roSnright q approx qP p_Sn qF qP
Eine bestimmte Messingsorte hat eine Dichte von roO. Wie viel Prozent Kupfer und wieviel Prozent Zink enthält sie? Die Dichte von Kupfer ist roCuO diejenige von Zink roSnO.
Solution:
Geg rho roO ro rho_Cu roCuO roCu rho_Sn roSnO roSn GesKupferanteilp_Cusipercent GesZinkanteilp_Snsipercent Für das Gesamtvolumen gilt al V V_rm Cu + V_rm Sn fracmrho fracm_rm Curho_rm Cu + fracm_rm Snrho_rm Sn fracmrho fracp_rm Cu mrho_rm Cu + frac-p_rm Cu mrho_rm Sn Wir können die Masse m wegkürzen und dann nach p_rm Cu auflösen: al fracrho fracp_rm Curho_rm Cu + frac-p_rm Curho_rm Sn uf rho_rm Cu rho_rm Sn fracrho_rm Cu rho_rm Snrho p_rm Cu rho_rm Sn + -p_rm Cu rho_rm Cu uf - rho_rm Cu fracrho_rm Cu rho_rm Snrho - rho_rm Cu p_rm Cu rho_rm Sn - rho_rm Cu uf :rho_rm Sn - rho_rm Cu p_rm Cu fracrho_rm Cu rho_rm Sn - rho rho_rm Curhorho_rm Sn - rho_rm Cu p_Cu pF fracroCu roSn - ro roCuro leftroSn - roCuright p approx pP p_Cu pF pP Aus Symmetriegründen gilt p_Sn qF fracroSn roCu - ro roSnro leftroCu - roSnright q approx qP p_Sn qF qP
Meta Information
Exercise:
Eine bestimmte Messingsorte hat eine Dichte von roO. Wie viel Prozent Kupfer und wieviel Prozent Zink enthält sie? Die Dichte von Kupfer ist roCuO diejenige von Zink roSnO.
Solution:
Geg rho roO ro rho_Cu roCuO roCu rho_Sn roSnO roSn GesKupferanteilp_Cusipercent GesZinkanteilp_Snsipercent Für das Gesamtvolumen gilt al V V_rm Cu + V_rm Sn fracmrho fracm_rm Curho_rm Cu + fracm_rm Snrho_rm Sn fracmrho fracp_rm Cu mrho_rm Cu + frac-p_rm Cu mrho_rm Sn Wir können die Masse m wegkürzen und dann nach p_rm Cu auflösen: al fracrho fracp_rm Curho_rm Cu + frac-p_rm Curho_rm Sn uf rho_rm Cu rho_rm Sn fracrho_rm Cu rho_rm Snrho p_rm Cu rho_rm Sn + -p_rm Cu rho_rm Cu uf - rho_rm Cu fracrho_rm Cu rho_rm Snrho - rho_rm Cu p_rm Cu rho_rm Sn - rho_rm Cu uf :rho_rm Sn - rho_rm Cu p_rm Cu fracrho_rm Cu rho_rm Sn - rho rho_rm Curhorho_rm Sn - rho_rm Cu p_Cu pF fracroCu roSn - ro roCuro leftroSn - roCuright p approx pP p_Cu pF pP Aus Symmetriegründen gilt p_Sn qF fracroSn roCu - ro roSnro leftroCu - roSnright q approx qP p_Sn qF qP
Eine bestimmte Messingsorte hat eine Dichte von roO. Wie viel Prozent Kupfer und wieviel Prozent Zink enthält sie? Die Dichte von Kupfer ist roCuO diejenige von Zink roSnO.
Solution:
Geg rho roO ro rho_Cu roCuO roCu rho_Sn roSnO roSn GesKupferanteilp_Cusipercent GesZinkanteilp_Snsipercent Für das Gesamtvolumen gilt al V V_rm Cu + V_rm Sn fracmrho fracm_rm Curho_rm Cu + fracm_rm Snrho_rm Sn fracmrho fracp_rm Cu mrho_rm Cu + frac-p_rm Cu mrho_rm Sn Wir können die Masse m wegkürzen und dann nach p_rm Cu auflösen: al fracrho fracp_rm Curho_rm Cu + frac-p_rm Curho_rm Sn uf rho_rm Cu rho_rm Sn fracrho_rm Cu rho_rm Snrho p_rm Cu rho_rm Sn + -p_rm Cu rho_rm Cu uf - rho_rm Cu fracrho_rm Cu rho_rm Snrho - rho_rm Cu p_rm Cu rho_rm Sn - rho_rm Cu uf :rho_rm Sn - rho_rm Cu p_rm Cu fracrho_rm Cu rho_rm Sn - rho rho_rm Curhorho_rm Sn - rho_rm Cu p_Cu pF fracroCu roSn - ro roCuro leftroSn - roCuright p approx pP p_Cu pF pP Aus Symmetriegründen gilt p_Sn qF fracroSn roCu - ro roSnro leftroCu - roSnright q approx qP p_Sn qF qP
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Messingsorte by TeXercises
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