Puffer für Lokomotive
About points...
We associate a certain number of points with each exercise.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
About difficulty...
We associate a certain difficulty with each exercise.
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
Question
Solution
Short
Video
\(\LaTeX\)
Need help? Yes, please!
The following quantities appear in the problem:
Zeit \(t\) / Energie \(E\) / Impuls \(p\) / Kraft \(F\) / Strecke \(s\) / Masse \(m\) / Beschleunigung \(a\) / Federkonstante \(D\) / Geschwindigkeit \(v\) /
The following formulas must be used to solve the exercise:
\(v = v_0 + at \quad \) \(s = \dfrac{v^2-v_0^2}{2a} \quad \) \(\sum E_{\scriptscriptstyle\rm tot} \stackrel{!}{=} \sum E_{\scriptscriptstyle\rm tot}' \quad \) \(F = Ds \quad \) \(\sum p_{\scriptscriptstyle\rm tot} \stackrel{!}{=} \sum p_{\scriptscriptstyle\rm tot}' \quad \) \(p = Ft \quad \) \(F = ma \quad \) \(D = D_1 + D_2 \quad \) \(\frac{1}{D} = \frac{1}{D_1} + \frac{1}{D_2} \quad \)
No explanation / solution video for this exercise has yet been created.
But there is a video to a similar exercise:
In case your browser prevents YouTube embedding: https://youtu.be/G6ame1ilF8Q
But there is a video to a similar exercise:
Exercise:
Eine Rangierlokomotive stösst einen Personenwagen mit einer Kraft von kN; dabei kommen sich die Rangierlokomotive und der Personenwagen cm näher. Die beiden Puffer des Personenwagens haben je eine Federkonstante von .enewtonpermeter. Berechne die Federkonstante eines Puffers der Rangierlokomotive.
Solution:
boxGegeben F kN .eN x cm .m D_ .enewtonpermeter boxGesucht textZweite Federkonstante D_sinewtonpermeter Die Ersatzfederkonstante von allen vier Puffern muss folge Härte haben: D fracFx fracN.m .enewtonpermeter Der Personenwagenpuffer kann ersetzt werden durch eine Feder der Härte D_P D_ .enewtonpermeter Damit muss die Ersatzfederkonstante der Rangierlokomotive folge Stärke haben: D_R leftfracD-fracD_Pright^- leftfracfracFx-fracD_right^- leftfracxF-fracD_right^- .enewtonpermeter Eine Feder der Rangierlokomotive ist damit: D_ fracD_R frac leftfracxF-fracD_right^- frac fracxD_-FD_F .enewtonpermeter boxbox D_ fracxD_-FD_F .enewtonpermeter
Eine Rangierlokomotive stösst einen Personenwagen mit einer Kraft von kN; dabei kommen sich die Rangierlokomotive und der Personenwagen cm näher. Die beiden Puffer des Personenwagens haben je eine Federkonstante von .enewtonpermeter. Berechne die Federkonstante eines Puffers der Rangierlokomotive.
Solution:
boxGegeben F kN .eN x cm .m D_ .enewtonpermeter boxGesucht textZweite Federkonstante D_sinewtonpermeter Die Ersatzfederkonstante von allen vier Puffern muss folge Härte haben: D fracFx fracN.m .enewtonpermeter Der Personenwagenpuffer kann ersetzt werden durch eine Feder der Härte D_P D_ .enewtonpermeter Damit muss die Ersatzfederkonstante der Rangierlokomotive folge Stärke haben: D_R leftfracD-fracD_Pright^- leftfracfracFx-fracD_right^- leftfracxF-fracD_right^- .enewtonpermeter Eine Feder der Rangierlokomotive ist damit: D_ fracD_R frac leftfracxF-fracD_right^- frac fracxD_-FD_F .enewtonpermeter boxbox D_ fracxD_-FD_F .enewtonpermeter
Meta Information
Exercise:
Eine Rangierlokomotive stösst einen Personenwagen mit einer Kraft von kN; dabei kommen sich die Rangierlokomotive und der Personenwagen cm näher. Die beiden Puffer des Personenwagens haben je eine Federkonstante von .enewtonpermeter. Berechne die Federkonstante eines Puffers der Rangierlokomotive.
Solution:
boxGegeben F kN .eN x cm .m D_ .enewtonpermeter boxGesucht textZweite Federkonstante D_sinewtonpermeter Die Ersatzfederkonstante von allen vier Puffern muss folge Härte haben: D fracFx fracN.m .enewtonpermeter Der Personenwagenpuffer kann ersetzt werden durch eine Feder der Härte D_P D_ .enewtonpermeter Damit muss die Ersatzfederkonstante der Rangierlokomotive folge Stärke haben: D_R leftfracD-fracD_Pright^- leftfracfracFx-fracD_right^- leftfracxF-fracD_right^- .enewtonpermeter Eine Feder der Rangierlokomotive ist damit: D_ fracD_R frac leftfracxF-fracD_right^- frac fracxD_-FD_F .enewtonpermeter boxbox D_ fracxD_-FD_F .enewtonpermeter
Eine Rangierlokomotive stösst einen Personenwagen mit einer Kraft von kN; dabei kommen sich die Rangierlokomotive und der Personenwagen cm näher. Die beiden Puffer des Personenwagens haben je eine Federkonstante von .enewtonpermeter. Berechne die Federkonstante eines Puffers der Rangierlokomotive.
Solution:
boxGegeben F kN .eN x cm .m D_ .enewtonpermeter boxGesucht textZweite Federkonstante D_sinewtonpermeter Die Ersatzfederkonstante von allen vier Puffern muss folge Härte haben: D fracFx fracN.m .enewtonpermeter Der Personenwagenpuffer kann ersetzt werden durch eine Feder der Härte D_P D_ .enewtonpermeter Damit muss die Ersatzfederkonstante der Rangierlokomotive folge Stärke haben: D_R leftfracD-fracD_Pright^- leftfracfracFx-fracD_right^- leftfracxF-fracD_right^- .enewtonpermeter Eine Feder der Rangierlokomotive ist damit: D_ fracD_R frac leftfracxF-fracD_right^- frac fracxD_-FD_F .enewtonpermeter boxbox D_ fracxD_-FD_F .enewtonpermeter
Contained in these collections
-
Puffer der Lokomotive by TeXercises
| Title | Matched on |
|---|---|
| Kraft der Rangierlokomotive | tags |
| Puffer für Lokomotive | tagstitle |
| Puffer für Lokomotive | tagstitle |
| Rangierlokomotive und Güterwagen | tags |
| Montage en série et en parallèle de ressorts | tags |
Similar exercises (19)
| Title | Matched on |
|---|---|
| Kraft der Rangierlokomotive | tags |
| Puffer für Lokomotive | tagstitle |
| Puffer für Lokomotive | tagstitle |
| Rangierlokomotive und Güterwagen | tags |
| Montage en série et en parallèle de ressorts | tags |
| Serie- und Parallelschaltung | tags |
| Federschaltungen | tags |
| Federschaltungen | tags |
| Zwei Federschaltungen | tags |
| Zwei Federschaltungen | tags |
| Zwei Federschaltungen | tags |
| Federschaltungen | tags |
| Zwei Federschaltungen | tags |
| Parallel geschaltete Federn zusammendrücken | tags |
| Parallel geschaltete Federn | tags |
| Parallel geschaltete Federn | tags |
| Halbierte Feder | tags |
| Parallel geschaltete Federn | tags |
| Absenken von Geländewagen | tags |