Exercise
https://texercises.raemilab.ch/exercise/springs-connected-in-series/
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The following quantities appear in the problem: Kraft \(F\) / Strecke \(s\) / Federkonstante \(D\) /
The following formulas must be used to solve the exercise: \(F = Ds \quad \) \(\frac{1}{D} = \frac{1}{D_1} + \frac{1}{D_2} \quad \)
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Exercise:
Two springs connected in series are stretched by a force of FO resulting in a total extension of sO. If the spring constant of the first spring is DaO calculate the spring constant of the second spring.

Solution:
boxGegeben F mN .N x .cm .m D_ millinewtonpermillimeter Npm boxGesucht textZweite Federkonstante D_sinewtonpermeter Die Ersatzfederkonstante der Schaltung beträgt: D fracFx frac.N.m .newtonpermeter Die Federkonstante der zweiten Feder ist somit: D_ leftfracD-fracD_right^- leftfracfracFx-fracD_right^- leftfracxF-fracD_right^- leftfrac.newtonpermeter-fracNpmright^- .eNpm boxbox D_ leftfracxF-fracD_right^- fracD_FD_x-F .eNpm
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Exercise:
Two springs connected in series are stretched by a force of FO resulting in a total extension of sO. If the spring constant of the first spring is DaO calculate the spring constant of the second spring.

Solution:
boxGegeben F mN .N x .cm .m D_ millinewtonpermillimeter Npm boxGesucht textZweite Federkonstante D_sinewtonpermeter Die Ersatzfederkonstante der Schaltung beträgt: D fracFx frac.N.m .newtonpermeter Die Federkonstante der zweiten Feder ist somit: D_ leftfracD-fracD_right^- leftfracfracFx-fracD_right^- leftfracxF-fracD_right^- leftfrac.newtonpermeter-fracNpmright^- .eNpm boxbox D_ leftfracxF-fracD_right^- fracD_FD_x-F .eNpm
Contained in these collections:
  1. 11 | 12
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Tags
feder, federgesetz, federn, hookesches gesetz, serieschaltung
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(2, default)
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2 (default)
Language
ENG (English)
Type
Calculative / Quantity
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