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Thickness of a hair

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Exercise

Physics Waves Electromagnetic Waves

https://texercises.raemilab.ch/exercise/thickness-of-a-hair/

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The following quantities appear in the problem: Anzahl \(N\) / Winkel \(\theta\) / Wellenlänge \(\lambda\) /

The following formulas must be used to solve the exercise: \(\sin(\alpha_k) = k \frac{\lambda}{s} \quad k=\pm1, \pm2, \pm3, \dots \quad \)

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Exercise:
A red laser beam wavelength laO is diffracted on a single hair. The diffraction pattern is observed on a screen LO from the hair. The first order minimum is measured to be aO from the central maximum. Calculate the thickness of the hair.

Solution:
We ase that a hair with thickness s produces the same diffraction pattern as a thin slit with width s. Since the distance of the first order minimum from the central maximum is much smaller than the distance between the hair and the screen the small angle approximation seems adequate: k fraclambdas fraca_kell It follows for the thickness of the hair s sF k times fracla times La s approx resultsP-

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Contained in these collections:

Lecture notes Diffraction & Interference by by

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Beugung am Spalt by TeXercises

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Attributes & Decorations

Branches	Electromagnetic Waves
Tags	diffraction, interference
Content image
Difficulty	(1, default)
Points	0 (default)
Language	(English)
Type	Calculative / Quantity
Decoration