Wasserdampf und Eis
About points...
We associate a certain number of points with each exercise.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
About difficulty...
We associate a certain difficulty with each exercise.
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
Question
Solution
Short
Video
\(\LaTeX\)
Need help? Yes, please!
The following quantities appear in the problem:
Masse \(m\) / Temperatur \(T\) / Volumen \(V\) / Wärme \(Q\) / spezifische latente Wärme \(L\) / Dichte \(\varrho\) / Wärmekapazität \(c\) /
The following formulas must be used to solve the exercise:
\(\varrho = \dfrac{m}{V} \quad \) \(Q = c \cdot m \cdot \Delta\vartheta \quad \) \(Q = m \cdot L_{\scriptscriptstyle\rm f} \quad \) \(Q = m \cdot L_{\scriptscriptstyle\rm v} \quad \) \(\sum Q^\nearrow \stackrel{!}{=} \sum Q^\swarrow \quad \)
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Don't forget to subscribe to our channel, like the videos and leave comments!
Exercise:
Wie viel Wasserdampf von TDO muss man zu mEO Eis bei TEO mischen um flüssiges Wasser der Temperatur TmO zu haben?
Solution:
Geg T_D TD m_E mE T_E TE T_m Tm L_v Lv L_f Lf c_W cW GesMasse des Wasserdampfsm_Dsikilogram Die beim Kondensieren und Abkühlen des Wasserdampfs abgegebene Wärme Q_ab muss gleich der beim Schmelzen und Erwärmen des Eises aufgenommenen Wärme Q_zu sein: Qab mustbe Qzu Delta T_a dTaF TD - Tm dTa Delta T_b dTbF Tm - TE dTb L_v m_D + c_W m_D Delta T_a L_f m_E + c_W m_E Delta T_b m_D fracm_E leftL_f + c_W Delta T_brightL_v + c_W Delta T_a fracm_E leftL_f + c_W leftdTbFrightrightL_v + c_W leftdTaFright fracmE leftLf + cW leftTm - TErightrightLv + cW leftTD - Tmright mD approx mDP m_D mDF mDP
Wie viel Wasserdampf von TDO muss man zu mEO Eis bei TEO mischen um flüssiges Wasser der Temperatur TmO zu haben?
Solution:
Geg T_D TD m_E mE T_E TE T_m Tm L_v Lv L_f Lf c_W cW GesMasse des Wasserdampfsm_Dsikilogram Die beim Kondensieren und Abkühlen des Wasserdampfs abgegebene Wärme Q_ab muss gleich der beim Schmelzen und Erwärmen des Eises aufgenommenen Wärme Q_zu sein: Qab mustbe Qzu Delta T_a dTaF TD - Tm dTa Delta T_b dTbF Tm - TE dTb L_v m_D + c_W m_D Delta T_a L_f m_E + c_W m_E Delta T_b m_D fracm_E leftL_f + c_W Delta T_brightL_v + c_W Delta T_a fracm_E leftL_f + c_W leftdTbFrightrightL_v + c_W leftdTaFright fracmE leftLf + cW leftTm - TErightrightLv + cW leftTD - Tmright mD approx mDP m_D mDF mDP
Meta Information
Exercise:
Wie viel Wasserdampf von TDO muss man zu mEO Eis bei TEO mischen um flüssiges Wasser der Temperatur TmO zu haben?
Solution:
Geg T_D TD m_E mE T_E TE T_m Tm L_v Lv L_f Lf c_W cW GesMasse des Wasserdampfsm_Dsikilogram Die beim Kondensieren und Abkühlen des Wasserdampfs abgegebene Wärme Q_ab muss gleich der beim Schmelzen und Erwärmen des Eises aufgenommenen Wärme Q_zu sein: Qab mustbe Qzu Delta T_a dTaF TD - Tm dTa Delta T_b dTbF Tm - TE dTb L_v m_D + c_W m_D Delta T_a L_f m_E + c_W m_E Delta T_b m_D fracm_E leftL_f + c_W Delta T_brightL_v + c_W Delta T_a fracm_E leftL_f + c_W leftdTbFrightrightL_v + c_W leftdTaFright fracmE leftLf + cW leftTm - TErightrightLv + cW leftTD - Tmright mD approx mDP m_D mDF mDP
Wie viel Wasserdampf von TDO muss man zu mEO Eis bei TEO mischen um flüssiges Wasser der Temperatur TmO zu haben?
Solution:
Geg T_D TD m_E mE T_E TE T_m Tm L_v Lv L_f Lf c_W cW GesMasse des Wasserdampfsm_Dsikilogram Die beim Kondensieren und Abkühlen des Wasserdampfs abgegebene Wärme Q_ab muss gleich der beim Schmelzen und Erwärmen des Eises aufgenommenen Wärme Q_zu sein: Qab mustbe Qzu Delta T_a dTaF TD - Tm dTa Delta T_b dTbF Tm - TE dTb L_v m_D + c_W m_D Delta T_a L_f m_E + c_W m_E Delta T_b m_D fracm_E leftL_f + c_W Delta T_brightL_v + c_W Delta T_a fracm_E leftL_f + c_W leftdTbFrightrightL_v + c_W leftdTaFright fracmE leftLf + cW leftTm - TErightrightLv + cW leftTD - Tmright mD approx mDP m_D mDF mDP
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Mischen mit Kondensations- und Schmelzwärme by TeXercises
| Title | Matched on |
|---|---|
| Wasserdampf und Eis | tagstitle |
| Wasserdampf und Eis | tagstitle |
| Wasserdampf und Eis | title |
| Wasser und Dampf mischen | tagsformula |
| Äthyläther | tags |
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