Dropping secret documents
About points...
We associate a certain number of points with each exercise.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
About difficulty...
We associate a certain difficulty with each exercise.
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
Question
Solution
Short
Video
\(\LaTeX\)
Need help? Yes, please!
The following quantities appear in the problem:
Zeit \(t\) / Geschwindigkeit \(v\) / Strecke \(s\) / Beschleunigung \(a\) / Winkel \(\theta\) /
The following formulas must be used to solve the exercise:
\(s = \dfrac{1}{2}at^2+v_0 t \quad \) \(s = vt \quad \) \(\tan\alpha = \dfrac{a}{b} \quad \)
No explanation / solution video to this exercise has yet been created.
Visit our YouTube-Channel to see solutions to other exercises.
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Visit our YouTube-Channel to see solutions to other exercises.
Don't forget to subscribe to our channel, like the videos and leave comments!
Exercise:
Spymaster Paul flying a constant kilometerperhour horizontally in a low-flying helicopter wants to drop secret documents o his contact's open car which is travelling kilometerperhour on a level highway .m below. At what angle to the horizontal should the car be in his sights when the packet is released?
Solution:
NewQtyve. NewQtyvz. NewQtyy.m % Geg v_ ve v_ vz y y % GesWinkelalphatext in sidegree % The relative velocity in horizontal direction between Paul and his contact is SolQtyvov_-v_veX-vzX al v_ voF ve - vz vo. % From a height of y it takes the document SolQtytsqrtfracygsqrt*yX/gMns al t tF sqrtfrac ygM t to fall o the car. Thus the document travels SolQtyxv_-v_ sqrtfracygvoX*tXm al x v_t xF ve - vz sqrtfrac ygM x further than the car. These x are the length of the opposite leg of a right-angled triangle. The adjacent leg corresponds to the height of y. Thus the angle at which the car should be in sight is SolQtyaarctanfracv_-v_ sqrtfracgyatandyX/xXdegree al alpha arctanfracyx aF arctanfracyx aP. % alpha aF aP
Spymaster Paul flying a constant kilometerperhour horizontally in a low-flying helicopter wants to drop secret documents o his contact's open car which is travelling kilometerperhour on a level highway .m below. At what angle to the horizontal should the car be in his sights when the packet is released?
Solution:
NewQtyve. NewQtyvz. NewQtyy.m % Geg v_ ve v_ vz y y % GesWinkelalphatext in sidegree % The relative velocity in horizontal direction between Paul and his contact is SolQtyvov_-v_veX-vzX al v_ voF ve - vz vo. % From a height of y it takes the document SolQtytsqrtfracygsqrt*yX/gMns al t tF sqrtfrac ygM t to fall o the car. Thus the document travels SolQtyxv_-v_ sqrtfracygvoX*tXm al x v_t xF ve - vz sqrtfrac ygM x further than the car. These x are the length of the opposite leg of a right-angled triangle. The adjacent leg corresponds to the height of y. Thus the angle at which the car should be in sight is SolQtyaarctanfracv_-v_ sqrtfracgyatandyX/xXdegree al alpha arctanfracyx aF arctanfracyx aP. % alpha aF aP
Meta Information
Exercise:
Spymaster Paul flying a constant kilometerperhour horizontally in a low-flying helicopter wants to drop secret documents o his contact's open car which is travelling kilometerperhour on a level highway .m below. At what angle to the horizontal should the car be in his sights when the packet is released?
Solution:
NewQtyve. NewQtyvz. NewQtyy.m % Geg v_ ve v_ vz y y % GesWinkelalphatext in sidegree % The relative velocity in horizontal direction between Paul and his contact is SolQtyvov_-v_veX-vzX al v_ voF ve - vz vo. % From a height of y it takes the document SolQtytsqrtfracygsqrt*yX/gMns al t tF sqrtfrac ygM t to fall o the car. Thus the document travels SolQtyxv_-v_ sqrtfracygvoX*tXm al x v_t xF ve - vz sqrtfrac ygM x further than the car. These x are the length of the opposite leg of a right-angled triangle. The adjacent leg corresponds to the height of y. Thus the angle at which the car should be in sight is SolQtyaarctanfracv_-v_ sqrtfracgyatandyX/xXdegree al alpha arctanfracyx aF arctanfracyx aP. % alpha aF aP
Spymaster Paul flying a constant kilometerperhour horizontally in a low-flying helicopter wants to drop secret documents o his contact's open car which is travelling kilometerperhour on a level highway .m below. At what angle to the horizontal should the car be in his sights when the packet is released?
Solution:
NewQtyve. NewQtyvz. NewQtyy.m % Geg v_ ve v_ vz y y % GesWinkelalphatext in sidegree % The relative velocity in horizontal direction between Paul and his contact is SolQtyvov_-v_veX-vzX al v_ voF ve - vz vo. % From a height of y it takes the document SolQtytsqrtfracygsqrt*yX/gMns al t tF sqrtfrac ygM t to fall o the car. Thus the document travels SolQtyxv_-v_ sqrtfracygvoX*tXm al x v_t xF ve - vz sqrtfrac ygM x further than the car. These x are the length of the opposite leg of a right-angled triangle. The adjacent leg corresponds to the height of y. Thus the angle at which the car should be in sight is SolQtyaarctanfracv_-v_ sqrtfracgyatandyX/xXdegree al alpha arctanfracyx aF arctanfracyx aP. % alpha aF aP
Contained in these collections
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Horizontaler Wurf by pw
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Horizontaler Wurf 2 by uz
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Spymaster Paul by TeXercises
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