Elektron kreist um Lithium-Kern -- Magnetfeld
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That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
About difficulty...
We associate a certain difficulty with each exercise.
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
Question
Solution
Short
Video
\(\LaTeX\)
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The following quantities appear in the problem:
Zeit \(t\) / Masse \(m\) / elektrische Stromstärke \(I\) / elektrische Ladung \(q, Q\) / Magnetische Flussdichte \(B\) / Kraft \(F\) / Geschwindigkeit \(v\) / Strecke \(s\) / Radius \(r\) / Umfang \(u\) /
The following formulas must be used to solve the exercise:
\(F = \frac{1}{4\pi\epsilon_0}\cdot \frac{q_1q_2}{r^2} \quad \) \(I = \dfrac{q}{t} \quad \) \(s = vt \quad \) \(u = 2\pi r \quad \) \(B = \dfrac{\mu_0 I}{2r} \quad \) \(F = m\dfrac{v^2}{r} \quad \)
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Exercise:
Ein Elektron umkreise den Kern eines Lithium-Atoms isotopeLi auf einer Kreisbahn mit dem Radius pqpm. Wie stark ist das Magnetfeld welches von diesem kreisen Elektron am Ort des Atomkerns erzeugt wird?
Solution:
Die Geschwindigkeit des Elektrons berechnet man wie folgt: F_textscriptsize el F_textscriptsize ZP fracpiepsilon_frace er^ mfracv^r v sqrtfracpiepsilon_ m_efrace^r pq.e Hierbei ist zu beachten dass bei der elektrischen Kraft die Ladungen e Kern des Lithium-Atoms und e Elektron eingesetzt werden müssen. Die Zeit welche das Elektron für einen Umlauf braucht ist dann: t fracsv fracpi rv pq.s Der dadurch entstehe Strom ist: I fracqt fracet pq.A Das beim Kern resultiere Magnetfeld ist schliesslich: B fracmu_ Ir pq.T
Ein Elektron umkreise den Kern eines Lithium-Atoms isotopeLi auf einer Kreisbahn mit dem Radius pqpm. Wie stark ist das Magnetfeld welches von diesem kreisen Elektron am Ort des Atomkerns erzeugt wird?
Solution:
Die Geschwindigkeit des Elektrons berechnet man wie folgt: F_textscriptsize el F_textscriptsize ZP fracpiepsilon_frace er^ mfracv^r v sqrtfracpiepsilon_ m_efrace^r pq.e Hierbei ist zu beachten dass bei der elektrischen Kraft die Ladungen e Kern des Lithium-Atoms und e Elektron eingesetzt werden müssen. Die Zeit welche das Elektron für einen Umlauf braucht ist dann: t fracsv fracpi rv pq.s Der dadurch entstehe Strom ist: I fracqt fracet pq.A Das beim Kern resultiere Magnetfeld ist schliesslich: B fracmu_ Ir pq.T
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Exercise:
Ein Elektron umkreise den Kern eines Lithium-Atoms isotopeLi auf einer Kreisbahn mit dem Radius pqpm. Wie stark ist das Magnetfeld welches von diesem kreisen Elektron am Ort des Atomkerns erzeugt wird?
Solution:
Die Geschwindigkeit des Elektrons berechnet man wie folgt: F_textscriptsize el F_textscriptsize ZP fracpiepsilon_frace er^ mfracv^r v sqrtfracpiepsilon_ m_efrace^r pq.e Hierbei ist zu beachten dass bei der elektrischen Kraft die Ladungen e Kern des Lithium-Atoms und e Elektron eingesetzt werden müssen. Die Zeit welche das Elektron für einen Umlauf braucht ist dann: t fracsv fracpi rv pq.s Der dadurch entstehe Strom ist: I fracqt fracet pq.A Das beim Kern resultiere Magnetfeld ist schliesslich: B fracmu_ Ir pq.T
Ein Elektron umkreise den Kern eines Lithium-Atoms isotopeLi auf einer Kreisbahn mit dem Radius pqpm. Wie stark ist das Magnetfeld welches von diesem kreisen Elektron am Ort des Atomkerns erzeugt wird?
Solution:
Die Geschwindigkeit des Elektrons berechnet man wie folgt: F_textscriptsize el F_textscriptsize ZP fracpiepsilon_frace er^ mfracv^r v sqrtfracpiepsilon_ m_efrace^r pq.e Hierbei ist zu beachten dass bei der elektrischen Kraft die Ladungen e Kern des Lithium-Atoms und e Elektron eingesetzt werden müssen. Die Zeit welche das Elektron für einen Umlauf braucht ist dann: t fracsv fracpi rv pq.s Der dadurch entstehe Strom ist: I fracqt fracet pq.A Das beim Kern resultiere Magnetfeld ist schliesslich: B fracmu_ Ir pq.T
Contained in these collections
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Kreisstrom Wasserstoffatom by TeXercises
| Title | Matched on |
|---|---|
| Abstand Elektron von Heliumkern | tags |
| Ringförmige Schleife | tags |
| Magnetfeld in Kreisstrom | tags |
| Wasserstoffatom -- Magnetfeld | tags |
| Radius von Leiterschleife | tags |
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| Title | Matched on |
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| Ringförmige Schleife | tags |
| Magnetfeld in Kreisstrom | tags |
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| Radius von Leiterschleife | tags |
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| Top oder Flop | tags |