Maturità 1
About points...
We associate a certain number of points with each exercise.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
About difficulty...
We associate a certain difficulty with each exercise.
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
Question
Solution
Short
Video
\(\LaTeX\)
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Don't forget to subscribe to our channel, like the videos and leave comments!
Exercise:
textbfMaturità --- Corso approfondito Si consideri la seguente funzione * f:mathbbC&to mathbbC z&mapsto wfzfracz+barz+iz+-ibarz- * abclist abc Determinare l'insieme di definizione di f; abc Porre zx+iy e wu+iv. Determinare uv in funzione di xy. abc Determinare l'equazione della curva mathcalC che viene trasformata da f nell'iperbole u v e rappresentarla graficamente. abc Determinare le soluzioni dell'equazione z^+f-i^. abclist
Solution:
abclist abc Per il dominio determiniamo quando il denomiatore è zero ossia quando * +iz+-ibarz-&iff +ix+iy+-ix-iy- &iff x-y- * Dunque x-y ossia il dominio è mathbbC tranne una retta. abc Inseriamo zx+iy otteno: * fracx+iy+x-iy+ix+iy+-ix-iy-fracx-iyx-y-overbracefracxx-y-^uoverbracfracyx-y-^vi * abc Abbiamo che * u v&iff -xyx-y-^ &iff x^-x+y^+y+ &iff x-^+y+/^ &iff fracx-^+fracy+/^/ * Si tratta dunque della seguente ellisse center tikzpicturescale. axisxcmycm axis linesmiddle enlargelimitsfalse axis line styleshorten -pt shorten -pt xlabel styleanchorwest atticklabel* cs:. xshiftpt ylabel styleanchorsouth atticklabel* cs:. yshiftpt xlabel x ylabel y xmin- xmax ymin- ymax ytick--... xtick--... minor x tick num minor y tick num minor grid styleblack! major grid styleblack! grid yminorgrids xminorgrids major tick lengthpt every tick/.style semithick draw rotate around:-.line widthpt -. ellipse cm and .cm; axis tikzpicture center abc Insero x e y- nella formula della parte b otteniamo come prima cosa f-i^leftfrac-----iright^-i^- Dunque l'equazione è z^- che ha le quattro soluzioni zsqrt cisleftfracpi k+rightquad kin abclist
textbfMaturità --- Corso approfondito Si consideri la seguente funzione * f:mathbbC&to mathbbC z&mapsto wfzfracz+barz+iz+-ibarz- * abclist abc Determinare l'insieme di definizione di f; abc Porre zx+iy e wu+iv. Determinare uv in funzione di xy. abc Determinare l'equazione della curva mathcalC che viene trasformata da f nell'iperbole u v e rappresentarla graficamente. abc Determinare le soluzioni dell'equazione z^+f-i^. abclist
Solution:
abclist abc Per il dominio determiniamo quando il denomiatore è zero ossia quando * +iz+-ibarz-&iff +ix+iy+-ix-iy- &iff x-y- * Dunque x-y ossia il dominio è mathbbC tranne una retta. abc Inseriamo zx+iy otteno: * fracx+iy+x-iy+ix+iy+-ix-iy-fracx-iyx-y-overbracefracxx-y-^uoverbracfracyx-y-^vi * abc Abbiamo che * u v&iff -xyx-y-^ &iff x^-x+y^+y+ &iff x-^+y+/^ &iff fracx-^+fracy+/^/ * Si tratta dunque della seguente ellisse center tikzpicturescale. axisxcmycm axis linesmiddle enlargelimitsfalse axis line styleshorten -pt shorten -pt xlabel styleanchorwest atticklabel* cs:. xshiftpt ylabel styleanchorsouth atticklabel* cs:. yshiftpt xlabel x ylabel y xmin- xmax ymin- ymax ytick--... xtick--... minor x tick num minor y tick num minor grid styleblack! major grid styleblack! grid yminorgrids xminorgrids major tick lengthpt every tick/.style semithick draw rotate around:-.line widthpt -. ellipse cm and .cm; axis tikzpicture center abc Insero x e y- nella formula della parte b otteniamo come prima cosa f-i^leftfrac-----iright^-i^- Dunque l'equazione è z^- che ha le quattro soluzioni zsqrt cisleftfracpi k+rightquad kin abclist
Meta Information
Exercise:
textbfMaturità --- Corso approfondito Si consideri la seguente funzione * f:mathbbC&to mathbbC z&mapsto wfzfracz+barz+iz+-ibarz- * abclist abc Determinare l'insieme di definizione di f; abc Porre zx+iy e wu+iv. Determinare uv in funzione di xy. abc Determinare l'equazione della curva mathcalC che viene trasformata da f nell'iperbole u v e rappresentarla graficamente. abc Determinare le soluzioni dell'equazione z^+f-i^. abclist
Solution:
abclist abc Per il dominio determiniamo quando il denomiatore è zero ossia quando * +iz+-ibarz-&iff +ix+iy+-ix-iy- &iff x-y- * Dunque x-y ossia il dominio è mathbbC tranne una retta. abc Inseriamo zx+iy otteno: * fracx+iy+x-iy+ix+iy+-ix-iy-fracx-iyx-y-overbracefracxx-y-^uoverbracfracyx-y-^vi * abc Abbiamo che * u v&iff -xyx-y-^ &iff x^-x+y^+y+ &iff x-^+y+/^ &iff fracx-^+fracy+/^/ * Si tratta dunque della seguente ellisse center tikzpicturescale. axisxcmycm axis linesmiddle enlargelimitsfalse axis line styleshorten -pt shorten -pt xlabel styleanchorwest atticklabel* cs:. xshiftpt ylabel styleanchorsouth atticklabel* cs:. yshiftpt xlabel x ylabel y xmin- xmax ymin- ymax ytick--... xtick--... minor x tick num minor y tick num minor grid styleblack! major grid styleblack! grid yminorgrids xminorgrids major tick lengthpt every tick/.style semithick draw rotate around:-.line widthpt -. ellipse cm and .cm; axis tikzpicture center abc Insero x e y- nella formula della parte b otteniamo come prima cosa f-i^leftfrac-----iright^-i^- Dunque l'equazione è z^- che ha le quattro soluzioni zsqrt cisleftfracpi k+rightquad kin abclist
textbfMaturità --- Corso approfondito Si consideri la seguente funzione * f:mathbbC&to mathbbC z&mapsto wfzfracz+barz+iz+-ibarz- * abclist abc Determinare l'insieme di definizione di f; abc Porre zx+iy e wu+iv. Determinare uv in funzione di xy. abc Determinare l'equazione della curva mathcalC che viene trasformata da f nell'iperbole u v e rappresentarla graficamente. abc Determinare le soluzioni dell'equazione z^+f-i^. abclist
Solution:
abclist abc Per il dominio determiniamo quando il denomiatore è zero ossia quando * +iz+-ibarz-&iff +ix+iy+-ix-iy- &iff x-y- * Dunque x-y ossia il dominio è mathbbC tranne una retta. abc Inseriamo zx+iy otteno: * fracx+iy+x-iy+ix+iy+-ix-iy-fracx-iyx-y-overbracefracxx-y-^uoverbracfracyx-y-^vi * abc Abbiamo che * u v&iff -xyx-y-^ &iff x^-x+y^+y+ &iff x-^+y+/^ &iff fracx-^+fracy+/^/ * Si tratta dunque della seguente ellisse center tikzpicturescale. axisxcmycm axis linesmiddle enlargelimitsfalse axis line styleshorten -pt shorten -pt xlabel styleanchorwest atticklabel* cs:. xshiftpt ylabel styleanchorsouth atticklabel* cs:. yshiftpt xlabel x ylabel y xmin- xmax ymin- ymax ytick--... xtick--... minor x tick num minor y tick num minor grid styleblack! major grid styleblack! grid yminorgrids xminorgrids major tick lengthpt every tick/.style semithick draw rotate around:-.line widthpt -. ellipse cm and .cm; axis tikzpicture center abc Insero x e y- nella formula della parte b otteniamo come prima cosa f-i^leftfrac-----iright^-i^- Dunque l'equazione è z^- che ha le quattro soluzioni zsqrt cisleftfracpi k+rightquad kin abclist
Contained in these collections
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Serie 5 - Coniche by gl
| Title | Creator | Matched on |
|---|---|---|
| Maturità 2 | gl | tagstitle |
| Maturità 1 | gl | title |

