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https://texercises.raemilab.ch/exercise/sostituzione-2/
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Exercise:
footnotehttps://www.youtube.com/watch?vNIEkYMskcw Calcola _^infty frac+coshxdx.

Solution:
Siccome coshxfrace^x+e^-xfrace^x+e^x otteniamo _^infty frac+coshxdx_^infty frace^xe^x+e^x+dx. Ora con la sosituzione ue^x così che due^xdx otteniamo l'egrale * _^inftyfracu+u^+du_^inftyfracu+^-du fracsqrt_^infty fracu+-sqrt-fracu++sqrtdu fracsqrtleftlnu+-sqrt-lnu++sqrtrightBig|_^infty fracsqrtlnleftfracu+-sqrtu++sqrtrightBig|_^infty fracsqrtlnleftfrac+sqrt-sqrtright *
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Exercise:
footnotehttps://www.youtube.com/watch?vNIEkYMskcw Calcola _^infty frac+coshxdx.

Solution:
Siccome coshxfrace^x+e^-xfrace^x+e^x otteniamo _^infty frac+coshxdx_^infty frace^xe^x+e^x+dx. Ora con la sosituzione ue^x così che due^xdx otteniamo l'egrale * _^inftyfracu+u^+du_^inftyfracu+^-du fracsqrt_^infty fracu+-sqrt-fracu++sqrtdu fracsqrtleftlnu+-sqrt-lnu++sqrtrightBig|_^infty fracsqrtlnleftfracu+-sqrtu++sqrtrightBig|_^infty fracsqrtlnleftfrac+sqrt-sqrtright *
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Calcolo integrale, Sostituzione
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(3, default)
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ITA (Italiano)
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Calculative / Quantity
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